PHPUnit9.0 断言-assertIsResource()

assertIsResource($actual[, $message = ''])

PHPUnit9.0 断言集合

当 ​$actual​ 的类型不是 ​resource ​时报告错误，错误讯息由 ​$message​ 指定。
​assertIsNotResource()​ 是与之相反的断言，接受相同的参数。
示例 1.40 assertIsResource() 的用法

<?php
use PHPUnit\Framework\TestCase;

class ResourceTest extends TestCase
{
    public function testFailure()
    {
        $this->assertIsResource(null);
    }
}

$ phpunit ResourceTest
PHPUnit |version|.0 by Sebastian Bergmann and contributors.

F

Time: 0 seconds, Memory: 5.00Mb

There was 1 failure:

1) ResourceTest::testFailure
Failed asserting that null is of type "resource".

/home/sb/ResourceTest.php:8

FAILURES!
Tests: 1, Assertions: 1, Failures: 1.