首页javaoptionalJava Stream - 如何输出(如果存在)可选

Java Stream - 如何输出(如果存在)可选

我们想知道如何输出(如果存在)可选。
import java.util.Arrays;
import java.util.List;
import java.util.Optional;

public class Main {

  public static void main(String[] args) throws Exception{
    List<Dish> menu =
        Arrays.asList( new Dish("pork", false, 800, Dish.Type.MEAT),
                       new Dish("beef", false, 700, Dish.Type.MEAT),
                       new Dish("chicken", false, 400, Dish.Type.MEAT),
                       new Dish("rice", true, 350, Dish.Type.OTHER),
                       new Dish("pizza", true, 550, Dish.Type.OTHER),
                       new Dish("prawns", false, 400, Dish.Type.FISH),
                       new Dish("salmon", false, 450, Dish.Type.FISH));
    // Filtering with predicate
    Optional<Dish> vegetarianMenu = menu.stream().filter(Dish::isVegetarian).findAny();

    vegetarianMenu.ifPresent(d -> System.out.println(d.getName()));


  }

}

class Dish {

  private final String name;
  private final boolean vegetarian;
  private final int calories;
  private final Type type;

  public Dish(String name, boolean vegetarian, int calories, Type type) {
      this.name = name;
      this.vegetarian = vegetarian;
      this.calories = calories;
      this.type = type;
  }

  public String getName() {
      return name;
  }

  public boolean isVegetarian() {
      return vegetarian;
  }

  public int getCalories() {
      return calories;
  }

  public Type getType() {
      return type;
  }

  public enum Type { MEAT, FISH, OTHER }

  @Override
  public String toString() {
      return name;
  }


}