Java HTML/XML - 如何解析XML并从属性获取值...

import java.io.ByteArrayInputStream;
import java.io.IOException;

import javax.xml.parsers.DocumentBuilder;
import javax.xml.parsers.DocumentBuilderFactory;
import javax.xml.parsers.ParserConfigurationException;

import org.w3c.dom.Document;
import org.w3c.dom.NamedNodeMap;
import org.w3c.dom.Node;
import org.w3c.dom.NodeList;
import org.xml.sax.SAXException;

public class Main {

  public static void main(String... args) throws IOException, SAXException,
      ParserConfigurationException {

    String xml = "<T rn='0'>"
        + "<I><P>UNKNOWN</P><K>UNKNOWN</K><N><O>UNKNOWN</O><P>UNKNOWN</P><U>UNKNOWN</U><N>UNKNOWN</N></N></I></T>";

    DocumentBuilderFactory dbf = DocumentBuilderFactory.newInstance();
    DocumentBuilder db = dbf.newDocumentBuilder();
    Document doc = db.parse(new ByteArrayInputStream(xml.getBytes("UTF-8")));

    print(doc.getDocumentElement(), "");
  }

  private static void print(Node e, String tab) {

    if (e.getNodeType() == Node.TEXT_NODE) {
      System.out.println(tab + e.getNodeValue());
      return;
    }

    System.out.print(tab + e.getNodeName());

    NamedNodeMap as = e.getAttributes();
    if (as != null && as.getLength() > 0) {
      System.out.print(" attributes=[");
      for (int i = 0; i < as.getLength(); i++)
        System.out.print((i == 0 ? "" : ", ") + as.item(i));
      System.out.print("]");
    }
    System.out.println();

    if (e.getNodeValue() != null)
      System.out.println(tab + " " + e.getNodeValue());

    NodeList childs = e.getChildNodes();
    for (int i = 0; i < childs.getLength(); i++)
      print(childs.item(i), tab + " ");
  }
}