tensorflow::ops::UniqueWithCounts

tensorflow::ops::UniqueWithCounts

#include <array_ops.h>

Finds unique elements in a 1-D tensor.

Summary

This operation returns a tensor y containing all of the unique elements of x sorted in the same order that they occur in x. This operation also returns a tensor idx the same size as x that contains the index of each value of x in the unique output y. Finally, it returns a third tensor count that contains the count of each element of y in x. In other words:

y[idx[i]] = x[i] for i in [0, 1,...,rank(x) - 1]

For example:

``` tensor 'x' is [1, 1, 2, 4, 4, 4, 7, 8, 8]

y, idx, count = unique_with_counts(x) y ==> [1, 2, 4, 7, 8] idx ==> [0, 0, 1, 2, 2, 2, 3, 4, 4] count ==> [2, 1, 3, 1, 2] ```

Arguments:

• scope: A Scope object
• x: 1-D.

Returns:

• Output y: 1-D.
• Output idx: 1-D.
• Output count: 1-D.

Public attributes

::tensorflow::Output count

::tensorflow::Output idx

::tensorflow::Output y

Public functions

 UniqueWithCounts(
  const ::tensorflow::Scope & scope,
  ::tensorflow::Input x
)

 UniqueWithCounts(
  const ::tensorflow::Scope & scope,
  ::tensorflow::Input x,
  const UniqueWithCounts::Attrs & attrs
)

Public static functions

Attrs OutIdx(
  DataType x
)