fold

ReQL command: fold

Command syntax

sequence.fold(base, function) → value
sequence.fold(base, function, emit=function[, final_emit=function]) → sequence

Description

Apply a function to a sequence in order, maintaining state via an accumulator. The fold command returns either a single value or a new sequence.

In its first form, fold operates like reduce, returning a value by applying a combining function to each element in a sequence. The combining function takes two parameters: the previous reduction result (the accumulator) and the current element. However, fold has the following differences from reduce:

  • it is guaranteed to proceed through the sequence from first element to last.
  • it passes an initial base value to the function with the first element in place of the previous reduction result.
combining_function(accumulator | base, element) → new_accumulator

In its second form, fold operates like concat_map, returning a new sequence rather than a single value. When an emit function is provided, fold will:

  • proceed through the sequence in order and take an initial base value, as above.
  • for each element in the sequence, call both the combining function and a separate emitting function. The emitting function takes three parameters: the previous reduction result (the accumulator), the current element, and the output from the combining function (the new value of the accumulator).

If provided, the emitting function must return a list.

emit(previous_accumulator, element, accumulator) → array

A finalEmit function may also be provided, which will be called at the end of the sequence. It takes a single parameter: the result of the last reduction through the iteration (the accumulator), or the original base value if the input sequence was empty. This function must return a list, which will be appended to fold’s output stream.

final_emit(accumulator | base) → array

Example: Concatenate words from a list.

r.table('words').order_by('id').fold('',
    lambda acc, word: acc + r.branch(acc == '', '', ', ') + word
).run(conn)

(This example could be implemented with reduce, but fold will preserve the order when words is a RethinkDB table or other stream, which is not guaranteed with reduce.)

Example: Return every other row in a table.

r.table('even_things').fold(0,
    lambda acc, row: acc + 1,
    emit=lambda acc, row, new_acc: r.branch((new_acc % 2 == 0), [row], [])
).run(conn)

The first function increments the accumulator each time it’s called, starting at 0; the second function, the emitting function, alternates between returning a single-item list containing the current row or an empty list. The fold command will return a concatenated list of each emitted value.

Example: Compute a five-day running average for a weight tracker.

r.table('tracker').filter({'name': 'bob'}).order_by('date')['weight'].fold(
    [],
    lambda acc, row: ([row] + acc).limit(5),
    emit=lambda acc, row, new_acc: r.branch(new_acc.size() == 5, [new_acc.avg()], [])
).run(conn)

Related commands

Get more help

Couldn't find what you were looking for?

© RethinkDB contributors
Licensed under the Creative Commons Attribution-ShareAlike 3.0 Unported License.
https://rethinkdb.com/api/python/fold/

在线笔记
App下载
App下载

扫描二维码

下载编程狮App

公众号
微信公众号

编程狮公众号

意见反馈
返回顶部