Calling Kotlin from Java

Calling Kotlin from Java

Kotlin code can be called from Java easily.

Properties

A Kotlin property is compiled to the following Java elements:

• A getter method, with the name calculated by prepending the get suffix;
• A setter method, with the name calculated by prepending the set suffix (only for var properties);
• A private field, with the same name as the property name (only for properties with backing fields).

For example, var firstName: String gets compiled to the following Java declarations:

private String firstName;

public String getFirstName() {
    return firstName;
}

public void setFirstName(String firstName) {
    this.firstName = firstName;
}

If the name of the property starts with is, a different name mapping rule is used: the name of the getter will be the same as the property name, and the name of the setter will be obtained by replacing is with set. For example, for a property isOpen, the getter will be called isOpen() and the setter will be called setOpen(). This rule applies for properties of any type, not just Boolean.

Package-Level Functions

All the functions and properties declared in a file example.kt inside a package org.foo.bar are put into a Java class named org.foo.bar.ExampleKt.

// example.kt
package demo

class Foo

fun bar() {
}

// Java
new demo.Foo();
demo.ExampleKt.bar();

The name of the generated Java class can be changed using the @JvmName annotation:

@file:JvmName("DemoUtils")

package demo

class Foo

fun bar() {
}

// Java
new demo.Foo();
demo.DemoUtils.bar();

Having multiple files which have the same generated Java class name (the same package and the same name or the same @JvmName annotation) is normally an error. However, the compiler has the ability to generate a single Java facade class which has the specified name and contains all the declarations from all the files which have that name. To enable the generation of such a facade, use the @JvmMultifileClass annotation in all of the files.

// oldutils.kt
@file:JvmName("Utils")
@file:JvmMultifileClass

package demo

fun foo() {
}

// newutils.kt
@file:JvmName("Utils")
@file:JvmMultifileClass

package demo

fun bar() {
}

// Java
demo.Utils.foo();
demo.Utils.bar();

Instance Fields

If you need to expose a Kotlin property as a field in Java, you need to annotate it with the @JvmField annotation. The field will have the same visibility as the underlying property. You can annotate a property with @JvmField if it has a backing field, is not private, does not have open, override or const modifiers, and is not a delegated property.

class C(id: String) {
    @JvmField val ID = id
}

// Java
class JavaClient {
    public String getID(C c) {
        return c.ID;
    }
}

Late-Initialized properties are also exposed as fields. The visibility of the field will be the same as the visibility of lateinit property setter.

Static Fields

Kotlin properties declared in a named object or a companion object will have static backing fields either in that named object or in the class containing the companion object.

Usually these fields are private but they can be exposed in one of the following ways:

• @JvmField annotation;
• lateinit modifier;
• const modifier.

Annotating such a property with @JvmField makes it a static field with the same visibility as the property itself.

class Key(val value: Int) {
    companion object {
        @JvmField
        val COMPARATOR: Comparator<Key> = compareBy<Key> { it.value }
    }
}

// Java
Key.COMPARATOR.compare(key1, key2);
// public static final field in Key class

A late-initialized property in an object or a companion object has a static backing field with the same visibility as the property setter.

object Singleton {
    lateinit var provider: Provider
}

// Java
Singleton.provider = new Provider();
// public static non-final field in Singleton class

Properties annotated with const (in classes as well as at the top level) are turned into static fields in Java:

// file example.kt

object Obj {
    const val CONST = 1
}

class C {
    companion object {
        const val VERSION = 9
    }
}

const val MAX = 239

In Java:

int c = Obj.CONST;
int d = ExampleKt.MAX;
int v = C.VERSION;

Static Methods

As mentioned above, Kotlin generates static methods for package-level functions. Kotlin can also generate static methods for functions defined in named objects or companion objects if you annotate those functions as @JvmStatic. For example:

class C {
    companion object {
        @JvmStatic fun foo() {}
        fun bar() {}
    }
}

Now, foo() is static in Java, while bar() is not:

C.foo(); // works fine
C.bar(); // error: not a static method

Same for named objects:

object Obj {
    @JvmStatic fun foo() {}
    fun bar() {}
}

In Java:

Obj.foo(); // works fine
Obj.bar(); // error
Obj.INSTANCE.bar(); // works, a call through the singleton instance
Obj.INSTANCE.foo(); // works too

@JvmStatic annotation can also be applied on a property of an object or a companion object making its getter and setter methods be static members in that object or the class containing the companion object.

Visibility

The Kotlin visibilities are mapped to Java in the following way:

• private members are compiled to private members;
• private top-level declarations are compiled to package-local declarations;
• protected remains protected (note that Java allows accessing protected members from other classes in the same package and Kotlin doesn't, so Java classes will have broader access to the code);
• internal declarations become public in Java. Members of internal classes go through name mangling, to make it harder to accidentally use them from Java and to allow overloading for members with the same signature that don't see each other according to Kotlin rules;
• public remains public.

KClass

Sometimes you need to call a Kotlin method with a parameter of type KClass. There is no automatic conversion from Class to KClass, so you have to do it manually by invoking the equivalent of the Class<T>.kotlin extension property:

kotlin.jvm.JvmClassMappingKt.getKotlinClass(MainView.class)

Handling signature clashes with @JvmName

Sometimes we have a named function in Kotlin, for which we need a different JVM name the byte code. The most prominent example happens due to type erasure:

fun List<String>.filterValid(): List<String>
fun List<Int>.filterValid(): List<Int>

These two functions can not be defined side-by-side, because their JVM signatures are the same: filterValid(Ljava/util/List;)Ljava/util/List;. If we really want them to have the same name in Kotlin, we can annotate one (or both) of them with @JvmName and specify a different name as an argument:

fun List<String>.filterValid(): List<String>

@JvmName("filterValidInt")
fun List<Int>.filterValid(): List<Int>

From Kotlin they will be accessible by the same name filterValid, but from Java it will be filterValid and filterValidInt.

The same trick applies when we need to have a property x alongside with a function getX():

val x: Int
    @JvmName("getX_prop")
    get() = 15

fun getX() = 10

Overloads Generation

Normally, if you write a Kotlin method with default parameter values, it will be visible in Java only as a full signature, with all parameters present. If you wish to expose multiple overloads to Java callers, you can use the @JvmOverloads annotation.

@JvmOverloads fun f(a: String, b: Int = 0, c: String = "abc") {
    ...
}

For every parameter with a default value, this will generate one additional overload, which has this parameter and all parameters to the right of it in the parameter list removed. In this example, the following methods will be generated:

// Java
void f(String a, int b, String c) { }
void f(String a, int b) { }
void f(String a) { }

The annotation also works for constructors, static methods etc. It can't be used on abstract methods, including methods defined in interfaces.

Note that, as described in Secondary Constructors, if a class has default values for all constructor parameters, a public no-argument constructor will be generated for it. This works even if the @JvmOverloads annotation is not specified.

Checked Exceptions

As we mentioned above, Kotlin does not have checked exceptions. So, normally, the Java signatures of Kotlin functions do not declare exceptions thrown. Thus if we have a function in Kotlin like this:

// example.kt
package demo

fun foo() {
    throw IOException()
}

And we want to call it from Java and catch the exception:

// Java
try {
  demo.Example.foo();
}
catch (IOException e) { // error: foo() does not declare IOException in the throws list
  // ...
}

we get an error message from the Java compiler, because foo() does not declare IOException. To work around this problem, use the @Throws annotation in Kotlin:

@Throws(IOException::class)
fun foo() {
    throw IOException()
}

Null-safety

When calling Kotlin functions from Java, nobody prevents us from passing null as a non-null parameter. That's why Kotlin generates runtime checks for all public functions that expect non-nulls. This way we get a NullPointerException in the Java code immediately.

Variant generics

When Kotlin classes make use of declaration-site variance, there are two options of how their usages are seen from the Java code. Let's say we have the following class and two functions that use it:

class Box<out T>(val value: T)

interface Base
class Derived : Base

fun boxDerived(value: Derived): Box<Derived> = Box(value)
fun unboxBase(box: Box<Base>): Base = box.value

A naive way of translating these functions into Java would be this:

Box<Derived> boxDerived(Derived value) { ... }
Base unboxBase(Box<Base> box) { ... }

The problem is that in Kotlin we can say unboxBase(boxDerived("s")), but in Java that would be impossible, because in Java the class Box is invariant in its parameter T, and thus Box<Derived> is not a subtype of Box<Base>. To make it work in Java we'd have to define unboxBase as follows:

Base unboxBase(Box<? extends Base> box) { ... }  

Here we make use of Java's wildcards types (? extends Base) to emulate declaration-site variance through use-site variance, because it is all Java has.

To make Kotlin APIs work in Java we generate Box<Super> as Box<? extends Super> for covariantly defined Box (or Foo<? super Bar> for contravariantly defined Foo) when it appears as a parameter. When it's a return value, we don't generate wildcards, because otherwise Java clients will have to deal with them (and it's against the common Java coding style). Therefore, the functions from our example are actually translated as follows:

// return type - no wildcards
Box<Derived> boxDerived(Derived value) { ... }
 
// parameter - wildcards 
Base unboxBase(Box<? extends Base> box) { ... }

NOTE: when the argument type is final, there's usually no point in generating the wildcard, so Box<String> is always Box<String>, no matter what position it takes.

If we need wildcards where they are not generated by default, we can use the @JvmWildcard annotation:

fun boxDerived(value: Derived): Box<@JvmWildcard Derived> = Box(value)
// is translated to 
// Box<? extends Derived> boxDerived(Derived value) { ... }

On the other hand, if we don't need wildcards where they are generated, we can use @JvmSuppressWildcards:

fun unboxBase(box: Box<@JvmSuppressWildcards Base>): Base = box.value
// is translated to 
// Base unboxBase(Box<Base> box) { ... }

NOTE: @JvmSuppressWildcards can be used not only on individual type arguments, but on entire declarations, such as functions or classes, causing all wildcards inside them to be suppressed.

Translation of type Nothing

The type Nothing is special, because it has no natural counterpart in Java. Indeed, every Java reference type, including java.lang.Void, accepts null as a value, and Nothing doesn't accept even that. So, this type cannot be accurately represented in the Java world. This is why Kotlin generates a raw type where an argument of type Nothing is used:

fun emptyList(): List<Nothing> = listOf()
// is translated to
// List emptyList() { ... }