Beautiful Soup 4 遍历
还拿"爱丽丝梦游仙境"的文档来做例子:
html_doc = """
<html><head><title>The Dormouse's story</title></head>
<body>
<p class="title"><b>The Dormouse's story</b></p>
<p class="story">Once upon a time there were three little sisters; and their names were
<a href="http://example.com/elsie" rel="external nofollow" target="_blank" rel="external nofollow" target="_blank" rel="external nofollow" target="_blank" rel="external nofollow" target="_blank" rel="external nofollow" target="_blank" rel="external nofollow" target="_blank" rel="external nofollow" target="_blank" class="sister" id="link1">Elsie</a>,
<a href="http://example.com/lacie" rel="external nofollow" target="_blank" rel="external nofollow" target="_blank" rel="external nofollow" target="_blank" rel="external nofollow" target="_blank" rel="external nofollow" target="_blank" rel="external nofollow" target="_blank" class="sister" id="link2">Lacie</a> and
<a href="http://example.com/tillie" rel="external nofollow" target="_blank" rel="external nofollow" target="_blank" rel="external nofollow" target="_blank" rel="external nofollow" target="_blank" rel="external nofollow" target="_blank" rel="external nofollow" target="_blank" class="sister" id="link3">Tillie</a>;
and they lived at the bottom of a well.</p>
<p class="story">...</p>
"""
from bs4 import BeautifulSoup
soup = BeautifulSoup(html_doc, 'html.parser')
通过这段例子来演示怎样从文档的一段内容找到另一段内容
子节点
一个Tag可能包含多个字符串或其它的Tag,这些都是这个Tag的子节点.Beautiful Soup提供了许多操作和遍历子节点的属性.
注意: Beautiful Soup中字符串节点不支持这些属性,因为字符串没有子节点
tag的名字
操作文档树最简单的方法就是告诉它你想获取的tag的name.如果想获取 <head> 标签,只要用 soup.head :
soup.head
# <head><title>The Dormouse's story</title></head>
soup.title
# <title>The Dormouse's story</title>
这是个获取tag的小窍门,可以在文档树的tag中多次调用这个方法.下面的代码可以获取<body>标签中的第一个<b>标签:
soup.body.b
# <b>The Dormouse's story</b>
通过点取属性的方式只能获得当前名字的第一个tag:
soup.a
# <a class="sister" href="http://example.com/elsie" rel="external nofollow" target="_blank" rel="external nofollow" target="_blank" rel="external nofollow" target="_blank" rel="external nofollow" target="_blank" rel="external nofollow" target="_blank" rel="external nofollow" target="_blank" rel="external nofollow" target="_blank" id="link1">Elsie</a>
如果想要得到所有的<a>标签,或是通过名字得到比一个tag更多的内容的时候,就需要用到 Searching the tree 中描述的方法,比如: find_all()
soup.find_all('a')
# [<a class="sister" href="http://example.com/elsie" rel="external nofollow" target="_blank" rel="external nofollow" target="_blank" rel="external nofollow" target="_blank" rel="external nofollow" target="_blank" rel="external nofollow" target="_blank" rel="external nofollow" target="_blank" rel="external nofollow" target="_blank" id="link1">Elsie</a>,
# <a class="sister" href="http://example.com/lacie" rel="external nofollow" target="_blank" rel="external nofollow" target="_blank" rel="external nofollow" target="_blank" rel="external nofollow" target="_blank" rel="external nofollow" target="_blank" rel="external nofollow" target="_blank" id="link2">Lacie</a>,
# <a class="sister" href="http://example.com/tillie" rel="external nofollow" target="_blank" rel="external nofollow" target="_blank" rel="external nofollow" target="_blank" rel="external nofollow" target="_blank" rel="external nofollow" target="_blank" rel="external nofollow" target="_blank" id="link3">Tillie</a>]
.contents 和 .children
tag的 .contents 属性可以将tag的子节点以列表的方式输出:
head_tag = soup.head
head_tag
# <head><title>The Dormouse's story</title></head>
head_tag.contents
[<title>The Dormouse's story</title>]
title_tag = head_tag.contents[0]
title_tag
# <title>The Dormouse's story</title>
title_tag.contents
# [u'The Dormouse's story']
BeautifulSoup 对象本身一定会包含子节点,也就是说<html>标签也是 BeautifulSoup 对象的子节点:
len(soup.contents)
# 1
soup.contents[0].name
# u'html'
字符串没有 .contents 属性,因为字符串没有子节点:
text = title_tag.contents[0]
text.contents
# AttributeError: 'NavigableString' object has no attribute 'contents'
通过tag的 .children 生成器,可以对tag的子节点进行循环:
for child in title_tag.children:
print(child)
# The Dormouse's story
.descendants
.contents 和 .children 属性仅包含tag的直接子节点.例如,<head>标签只有一个直接子节点<title>
head_tag.contents
# [<title>The Dormouse's story</title>]
但是<title>标签也包含一个子节点:字符串 “The Dormouse’s story”,这种情况下字符串 “The Dormouse’s story”也属于<head>标签的子孙节点。.descendants 属性可以对所有tag的子孙节点进行递归循环 [5] :
for child in head_tag.descendants:
print(child)
# <title>The Dormouse's story</title>
# The Dormouse's story
上面的例子中, <head>标签只有一个子节点,但是有2个子孙节点:<head>节点和<head>的子节点, BeautifulSoup 有一个直接子节点(<html>节点),却有很多子孙节点:
len(list(soup.children))
# 1
len(list(soup.descendants))
# 25
.string
如果tag只有一个 NavigableString 类型子节点,那么这个tag可以使用 .string 得到子节点:
title_tag.string
# u'The Dormouse's story'
如果一个tag仅有一个子节点,那么这个tag也可以使用 .string 方法,输出结果与当前唯一子节点的 .string 结果相同:
head_tag.contents
# [<title>The Dormouse's story</title>]
head_tag.string
# u'The Dormouse's story'
如果tag包含了多个子节点,tag就无法确定 .string 方法应该调用哪个子节点的内容, .string 的输出结果是 None :
print(soup.html.string)
# None
.strings 和 stripped_strings
如果tag中包含多个字符串,可以使用 .strings 来循环获取:
for string in soup.strings:
print(repr(string))
# u"The Dormouse's story"
# u'\n\n'
# u"The Dormouse's story"
# u'\n\n'
# u'Once upon a time there were three little sisters; and their names were\n'
# u'Elsie'
# u',\n'
# u'Lacie'
# u' and\n'
# u'Tillie'
# u';\nand they lived at the bottom of a well.'
# u'\n\n'
# u'...'
# u'\n'
输出的字符串中可能包含了很多空格或空行,使用 .stripped_strings 可以去除多余空白内容:
for string in soup.stripped_strings:
print(repr(string))
# u"The Dormouse's story"
# u"The Dormouse's story"
# u'Once upon a time there were three little sisters; and their names were'
# u'Elsie'
# u','
# u'Lacie'
# u'and'
# u'Tillie'
# u';\nand they lived at the bottom of a well.'
# u'...'
全部是空格的行会被忽略掉,段首和段末的空白会被删除
父节点
继续分析文档树,每个tag或字符串都有父节点:被包含在某个tag中
.parent
通过 .parent 属性来获取某个元素的父节点.在例子“爱丽丝”的文档中,<head>标签是<title>标签的父节点:
title_tag = soup.title
title_tag
# <title>The Dormouse's story</title>
title_tag.parent
# <head><title>The Dormouse's story</title></head>
文档title的字符串也有父节点:<title>标签
title_tag.string.parent
# <title>The Dormouse's story</title>
文档的顶层节点比如<html>的父节点是 BeautifulSoup 对象:
html_tag = soup.html
type(html_tag.parent)
# <class 'bs4.BeautifulSoup'>
BeautifulSoup 对象的 .parent 是None:
print(soup.parent)
# None
.parents
通过元素的 .parents 属性可以递归得到元素的所有父辈节点,下面的例子使用了 .parents 方法遍历了<a>标签到根节点的所有节点.
link = soup.a
link
# <a class="sister" href="http://example.com/elsie" rel="external nofollow" target="_blank" rel="external nofollow" target="_blank" rel="external nofollow" target="_blank" rel="external nofollow" target="_blank" rel="external nofollow" target="_blank" rel="external nofollow" target="_blank" rel="external nofollow" target="_blank" id="link1">Elsie</a>
for parent in link.parents:
if parent is None:
print(parent)
else:
print(parent.name)
# p
# body
# html
# [document]
# None
兄弟节点
看一段简单的例子:
sibling_soup = BeautifulSoup("<a><b>text1</b><c>text2</c></b></a>")
print(sibling_soup.prettify())
# <html>
# <body>
# <a>
# <b>
# text1
# </b>
# <c>
# text2
# </c>
# </a>
# </body>
# </html>
因为<b>标签和<c>标签是同一层:他们是同一个元素的子节点,所以<b>和<c>可以被称为兄弟节点.一段文档以标准格式输出时,兄弟节点有相同的缩进级别.在代码中也可以使用这种关系.
.next_sibling 和 .previous_sibling
在文档树中,使用 .next_sibling 和 .previous_sibling 属性来查询兄弟节点:
sibling_soup.b.next_sibling
# <c>text2</c>
sibling_soup.c.previous_sibling
# <b>text1</b>
<b>标签有 .next_sibling 属性,但是没有 .previous_sibling 属性,因为<b>标签在同级节点中是第一个.同理,<c>标签有 .previous_sibling 属性,却没有 .next_sibling 属性:
print(sibling_soup.b.previous_sibling)
# None
print(sibling_soup.c.next_sibling)
# None
例子中的字符串“text1”和“text2”不是兄弟节点,因为它们的父节点不同:
sibling_soup.b.string
# u'text1'
print(sibling_soup.b.string.next_sibling)
# None
实际文档中的tag的 .next_sibling 和 .previous_sibling 属性通常是字符串或空白. 看看“爱丽丝”文档:
<a href="http://example.com/elsie" rel="external nofollow" target="_blank" rel="external nofollow" target="_blank" rel="external nofollow" target="_blank" rel="external nofollow" target="_blank" rel="external nofollow" target="_blank" rel="external nofollow" target="_blank" rel="external nofollow" target="_blank" class="sister" id="link1">Elsie</a>
<a href="http://example.com/lacie" rel="external nofollow" target="_blank" rel="external nofollow" target="_blank" rel="external nofollow" target="_blank" rel="external nofollow" target="_blank" rel="external nofollow" target="_blank" rel="external nofollow" target="_blank" class="sister" id="link2">Lacie</a>
<a href="http://example.com/tillie" rel="external nofollow" target="_blank" rel="external nofollow" target="_blank" rel="external nofollow" target="_blank" rel="external nofollow" target="_blank" rel="external nofollow" target="_blank" rel="external nofollow" target="_blank" class="sister" id="link3">Tillie</a>
如果以为第一个<a>标签的 .next_sibling 结果是第二个<a>标签,那就错了,真实结果是第一个<a>标签和第二个<a>标签之间的顿号和换行符:
link = soup.a
link
# <a class="sister" href="http://example.com/elsie" rel="external nofollow" target="_blank" rel="external nofollow" target="_blank" rel="external nofollow" target="_blank" rel="external nofollow" target="_blank" rel="external nofollow" target="_blank" rel="external nofollow" target="_blank" rel="external nofollow" target="_blank" id="link1">Elsie</a>
link.next_sibling
# u',\n'
第二个<a>标签是顿号的 .next_sibling 属性:
link.next_sibling.next_sibling
# <a class="sister" href="http://example.com/lacie" rel="external nofollow" target="_blank" rel="external nofollow" target="_blank" rel="external nofollow" target="_blank" rel="external nofollow" target="_blank" rel="external nofollow" target="_blank" rel="external nofollow" target="_blank" id="link2">Lacie</a>
.next_siblings 和 .previous_siblings
通过 .next_siblings 和 .previous_siblings 属性可以对当前节点的兄弟节点迭代输出:
for sibling in soup.a.next_siblings:
print(repr(sibling))
# u',\n'
# <a class="sister" href="http://example.com/lacie" rel="external nofollow" target="_blank" rel="external nofollow" target="_blank" rel="external nofollow" target="_blank" rel="external nofollow" target="_blank" rel="external nofollow" target="_blank" rel="external nofollow" target="_blank" id="link2">Lacie</a>
# u' and\n'
# <a class="sister" href="http://example.com/tillie" rel="external nofollow" target="_blank" rel="external nofollow" target="_blank" rel="external nofollow" target="_blank" rel="external nofollow" target="_blank" rel="external nofollow" target="_blank" rel="external nofollow" target="_blank" id="link3">Tillie</a>
# u'; and they lived at the bottom of a well.'
# None
for sibling in soup.find(id="link3").previous_siblings:
print(repr(sibling))
# ' and\n'
# <a class="sister" href="http://example.com/lacie" rel="external nofollow" target="_blank" rel="external nofollow" target="_blank" rel="external nofollow" target="_blank" rel="external nofollow" target="_blank" rel="external nofollow" target="_blank" rel="external nofollow" target="_blank" id="link2">Lacie</a>
# u',\n'
# <a class="sister" href="http://example.com/elsie" rel="external nofollow" target="_blank" rel="external nofollow" target="_blank" rel="external nofollow" target="_blank" rel="external nofollow" target="_blank" rel="external nofollow" target="_blank" rel="external nofollow" target="_blank" rel="external nofollow" target="_blank" id="link1">Elsie</a>
# u'Once upon a time there were three little sisters; and their names were\n'
# None
回退和前进
看一下“爱丽丝” 文档:
<html><head><title>The Dormouse's story</title></head>
<p class="title"><b>The Dormouse's story</b></p>
HTML解析器把这段字符串转换成一连串的事件: “打开<html>标签”,”打开一个<head>标签”,”打开一个<title>标签”,”添加一段字符串”,”关闭<title>标签”,”打开<p>标签”,等等.Beautiful Soup提供了重现解析器初始化过程的方法.
.next_element 和 .previous_element
.next_element 属性指向解析过程中下一个被解析的对象(字符串或tag),结果可能与 .next_sibling 相同,但通常是不一样的.
这是“爱丽丝”文档中最后一个<a>标签,它的 .next_sibling 结果是一个字符串,因为当前的解析过程因为当前的解析过程因为遇到了<a>标签而中断了:
last_a_tag = soup.find("a", id="link3")
last_a_tag
# <a class="sister" href="http://example.com/tillie" rel="external nofollow" target="_blank" rel="external nofollow" target="_blank" rel="external nofollow" target="_blank" rel="external nofollow" target="_blank" rel="external nofollow" target="_blank" rel="external nofollow" target="_blank" id="link3">Tillie</a>
last_a_tag.next_sibling
# '; and they lived at the bottom of a well.'
但这个<a>标签的 .next_element 属性结果是在<a>标签被解析之后的解析内容,不是<a>标签后的句子部分,应该是字符串”Tillie”:
last_a_tag.next_element
# u'Tillie'
这是因为在原始文档中,字符串“Tillie” 在分号前出现,解析器先进入<a>标签,然后是字符串“Tillie”,然后关闭</a>标签,然后是分号和剩余部分.分号与<a>标签在同一层级,但是字符串“Tillie”会被先解析.
.previous_element 属性刚好与 .next_element 相反,它指向当前被解析的对象的前一个解析对象:
last_a_tag.previous_element
# u' and\n'
last_a_tag.previous_element.next_element
# <a class="sister" href="http://example.com/tillie" rel="external nofollow" target="_blank" rel="external nofollow" target="_blank" rel="external nofollow" target="_blank" rel="external nofollow" target="_blank" rel="external nofollow" target="_blank" rel="external nofollow" target="_blank" id="link3">Tillie</a>
.next_elements 和 .previous_elements
通过 .next_elements 和 .previous_elements 的迭代器就可以向前或向后访问文档的解析内容,就好像文档正在被解析一样:
for element in last_a_tag.next_elements:
print(repr(element))
# u'Tillie'
# u';\nand they lived at the bottom of a well.'
# u'\n\n'
# <p class="story">...</p>
# u'...'
# u'\n'
# None
更多建议：